Three Common Chords in Three Concurrent Circles
When two circles intersect, the common chord through one of the intersections is the longest when its endpoints are diametrically opposite the other point of intersection in the two circles. This property is extended to three concurrent circles.
Circles \((A)\), \((B)\), and \((C)\) concur at point \(D\). Chords \(KL,\) \(LM\), and \(KM\) pass through the other points of intersection \(G,H,F\)
Prove that, if one of the segments \(DK\), \(DL\), \(DM\) is a diameter in the respective circle, so are the other two.
(The applet below illustrates the problem.)
14 January 2015, Created with GeoGebra
Created with GeoGebra
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