Two Symmetric Triangles Are Directly Equidecomposable II

The problem #9 in a delightful collection Which Way Did the Bicycle Go? reads:

My attempts at solving this problem led me a little astray. I was put back on the right track with the help from Nathan Bowler. To all intents and purposes this is indeed the intended solution, but the manner in which it's arrived at is different.

References

1. J. Konhauser, D. Velleman, S. Wagon, Which Way Did the Bicycle Go?, MAA, 1996, #9

Equidecomposition by Dissection

1. Carpet With a Hole
2. Equidecomposition of a Rectangle and a Square
3. Equidecomposition of Two Parallelograms
4. Equidecomposition of Two Rectangles
5. Equidecomposition of a Triangle and a Rectangle
6. Equidecomposition of a Triangle and a Rectangle II
7. Perigal's Proof of the Pythagorean Theorem
8. Two Symmetric Triangles Are Directly Equidecomposable
9. Wallace-Bolyai-Gerwien Theorem

Copyright © 1996-2009 Alexander Bogomolny

Solution

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Copyright © 1996-2009 Alexander Bogomolny