Angle Bisectors On Circumcircle

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A Mathematical Droodle


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Angle Bisector

  • Angle Bisector
  • Angle Bisector Theorem
  • All about angle bisectors
  • Angle Bisectors in Ellipse
  • Angle Bisectors in Ellipse II
  • Angle Bisector in Equilateral Trapezoid
  • Angle Bisector in Rectangle
  • Property of Angle Bisectors
  • Property of Angle Bisectors II
  • External Angle Bisectors
  • Projections on Internal and External Angle Bisectors
  • Angle Bisectors in a Quadrilateral - Cyclic and Otherwise
  • Problem: Angle Bisectors in a Quadrilateral
  • |Activities| |Contact| |Front page| |Contents| |Geometry| |Store|

    Copyright © 1996-2012 Alexander Bogomolny

    The applet attempts to suggest the following problem [Tao, pp. 50-51]:

    ABC is a triangle that is inscribed in a circle. The angle bisectors of A, B, C meet the circle in D, E, F, respectively. Show that AD is perpendicular to EF.


    This applet requires Sun's Java VM 2 which your browser may perceive as a popup. Which it is not. If you want to see the applet work, visit Sun's website at http://www.java.com/en/download/index.jsp, download and install Java VM and enjoy the applet.


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    What if applet does not run?

    We'll concentrate on ΔFIM. By a theorem of the inscribed angles,

    ∠IFM = ∠CFE = ∠CBE = ∠B/2.

    By a the theorem of the secant angles (or with the help of the Exterior Angle Theorem),

    ∠FIM = ∠ACI + ∠CAI = ∠C/2 + ∠A/2.

    It follows that in ΔFIM, angles at F and I add up to 90°:

    ∠A/2 + ∠B/2 + ∠C/2 = 180°/2 = 90°.

    We conclude that the remaining angle at M is necessarily right.

    References

    1. T. Tao, Solving Mathematical Problems, Oxford University Press

    |Activities| |Contact| |Front page| |Contents| |Geometry| |Store|

    Copyright © 1996-2012 Alexander Bogomolny

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