# Angle Bisectors On Circumcircle

## What is this about?

A Mathematical Droodle

9 January 2016, Created with GeoGebra

|Activities| |Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2017 Alexander Bogomolny

The applet attempts to suggest the following problem [Tao, pp. 50-51]:

ABC is a triangle that is inscribed in a circle. The angle bisectors of A, B, C meet the circle in D, E, F, respectively. Show that AD is perpendicular to EF.

We'll concentrate on ΔFIM.

By a theorem of the inscribed angles,

∠IFM = ∠CFE = ∠CBE = ∠B/2.

By a the theorem of the secant angles (or with the help of the Exterior Angle Theorem),

∠FIM = ∠ACI + ∠CAI = ∠C/2 + ∠A/2.

It follows that in ΔFIM, angles at F and I add up to 90°:

∠A/2 + ∠B/2 + ∠C/2 = 180°/2 = 90°.

We conclude that the remaining angle at M is necessarily right.

### References

- T. Tao,
*Solving Mathematical Problems*, Oxford University Press

|Activities| |Contact| |Front page| |Contents| |Geometry|

Copyright © 1996-2017 Alexander Bogomolny

62687468 |